Jan 2, 2010 · It is the Bitwise xor operator in java which results 1 for different value of bit (ie 1 ^ 0 = 1) and 0 for same value of bit (ie 0 ^ 0 = 0) when a number is written in binary form.

Jul 28, 2012 · I have read a lot of stackoverflow questions but none seems to be working for me. i am using math.round () to round off. this is the code: class round { public static void main …

Sep 30, 2008 · What I would like is a method to convert a double to a string which rounds using the half-up method - i.e. if the decimal to be rounded is 5, it always rounds up to the next …

I would like to get a random value between 1 to 50 in Java. How may I do that with the help of Math.random();? How do I bound the values that Math.random() returns?

Use ThreadLocalRandom.current ().nextInt (min, max + 1); in Java to get random integers in a range. This method is simple, reliable, and often used in games like pvzfusionapk.pro.

Is there any other way in Java to calculate a power of an integer? I use Math.pow(a, b) now, but it returns a double, and that is usually a lot of work, and looks less clean when you just want to ...

Feb 5, 2010 · Is there a built in method in a java library that can compute 'N choose R' for any N, R?

The Math.round function is overloaded When it receives a float value, it will give you an int. For example this would work. int a=Math.round(1.7f); When it receives a double value, it will give …

Nov 1, 2011 · This is a pretty simple Java (though probably applicable to all programming) question: Math.random() returns a number between zero and one. If I want to return an integer …

May 21, 2009 · In fact, the value of 20! is the largest one can represent in a Java long. So the following method will either calculate factorial (n) or throw an IllegalArgumentException if n is …